How many campers does a 208 V, three-phase heater that draws 3598 W support?

How many campers does a 208 V, three-phase heater that draws 3598 W support?

• A. 8 campers
• B. 9 campers
• C. 10 campers
• D. 11 campers

Answer: (C)

To determine how many campers a 208 V, three-phase heater that draws 3598 W can support, you start by calculating the current drawn by the heater. The formula for calculating power in a three-phase system is: Power (W) = √3 × Voltage (V) × Current (I). Rearranging this formula to solve for the current provides: Current (I) = Power (W) / (√3 × Voltage (V)). Substituting the known values: Current (I) = 3598 W / (√3 × 208 V). Calculating the denominator, √3 is approximately 1.732, which gives: Current (I) ≈ 3598 W / (1.732 × 208 V). Now calculating that provides the current about 10 A (rounded). Next, to ascertain how many campers that current can support, one typically needs to know the per-camper power consumption. If each camper requires around 350 W (a common estimate when considering heating and electrical needs), then: Total number of campers = Total Power / Power per camper = 3598 W / 350 W ≈ 10.3. Since we cannot have a fraction of a

To determine how many campers a 208 V, three-phase heater that draws 3598 W can support, you start by calculating the current drawn by the heater. The formula for calculating power in a three-phase system is:

Power (W) = √3 × Voltage (V) × Current (I).

Rearranging this formula to solve for the current provides:

Current (I) = Power (W) / (√3 × Voltage (V)).

Substituting the known values:

Current (I) = 3598 W / (√3 × 208 V).

Calculating the denominator, √3 is approximately 1.732, which gives:

Current (I) ≈ 3598 W / (1.732 × 208 V).

Now calculating that provides the current about 10 A (rounded).

Next, to ascertain how many campers that current can support, one typically needs to know the per-camper power consumption. If each camper requires around 350 W (a common estimate when considering heating and electrical needs), then:

Total number of campers = Total Power / Power per camper = 3598 W / 350 W ≈ 10.3.

Since we cannot have a fraction of a